Bisectoare

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Amaranth
Thales
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Joined: Sun Oct 19, 2008 5:44 pm

Bisectoare

Post by Amaranth »

Se da unghiul AOB, cu bisectoarea [OC. Unghiul AOC fiind la randul lui "bisectat" de [OD. Iar Unghiul COD are ca bisectoare pe [OE, care are masura de 2*.

Aflati toate masurile prin:

a) inmultire repetata.
b) putere. :wink:
In all this world there is only one pure and magic thing... and it is called PURPLE!
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miruna.lazar
Bernoulli
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Joined: Wed Oct 08, 2008 8:41 pm
Location: Tulcea

Post by miruna.lazar »

m(coe)= 2* => m(eod)= 2* => m(cod)= 2 x 2 =2^2= 4*=> m(aoc) =4 x 2= 2 x 2 x 2 = 2^3 = 8* => m(aob)= 2 x 2 x 2 x 2 = 2^4 = 16*
( ^ _ ^ )
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