ECUATIE

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miruna.lazar
Bernoulli
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ECUATIE

Post by miruna.lazar »

Ah! Este duminica, foarte linistit afara. Azi n-am lucrat deloc la mate, asa ca mama mi-a zis sa rezolv o ecuatie:
(x+1) + (x+2) +(x+3)+...+(x+100 ) = 15050.
Am rezolvat-o, foarte usoara ! Am obtinut un rezultat cu suma cifrelor 1. Tare, nu ? Puteti sa faceti si voi ecuatia asta sa vedeti daca am dreptate?
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Dorobantu Razvan
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Post by Dorobantu Razvan »

\( x+1+x+2+...+x+100=15050 \)(am renuntat la paranteze)
Daca fiecarui nr. \( x \) ii corespundeun nr. de la 1 la 100, sunt 100 \( x \)
\( 100x+1+2+3+4+...+100=15050 \)
(Formula lui Gauss)\( 100x+[(1+100)100:2]=15050 \)
\( 100x+(10100:2)=15050 \)
\( 100x+5050=15050 \)
\( 100x=10000 \)
\( x=10 \)
\( 1+0=1 \)
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miruna.lazar
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Location: Tulcea

Post by miruna.lazar »

Nu e bine :(
Last edited by miruna.lazar on Mon Mar 23, 2009 10:19 pm, edited 1 time in total.
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Amaranth
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Post by Amaranth »

Pot sa zic eu? :roll:
Dorobantu Razvan wrote: \( 100x=10000 \)
\( x=10 \)
10 * 100= 1000
100 * 100 = 10000
Deci x= 100
In all this world there is only one pure and magic thing... and it is called PURPLE!
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