Exercitiu teoretic

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opincariumihai
Thales
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Exercitiu teoretic

Post by opincariumihai »

Daca \( A,B\in{M_n(C)} \) si \( \tr(A^k)=\tr(B^k) \) \( \forall k\in{N} \), atunci \( \det A=\det B \) ?
Marius Mainea
Gauss
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Post by Marius Mainea »

Da. Folosim Formulele lui Newton de aici.
opincariumihai
Thales
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Location: BRAD

Post by opincariumihai »

Marius Mainea wrote:Da. Folosim Formulele lui Newton de aici.
Pai atunci de ce nu vreti sa abordati problema de aici in cazul general folosind indicatia de mai sus?
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